[py]
# Problem 1
# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9.
# The sum of these multiples is 23.
# Find the sum of all the multiples of 3 or 5 below 1000.
sum = 0
for i in range(1000):
if (i % 3 == 0) or (i % 5 == 0):
sum += i
else:
print(sum)
[/py]
[py]
233168
[/py]
コメント
素朴にやるだけ。